Net Ionic Equations and Reactions

The video tutorial explains how to write a balanced net ionic equation for the reaction between sulfuric acid and strontium hydroxide. It begins with balancing the molecular equation, then determining the states of substances using solubility tables. The tutorial proceeds to split strong electrolytes into ions for the complete ionic equation and identifies the net ionic equation by removing spectator ions. Finally, it concludes with verifying the balance of the net ionic equation.

What is the first step in writing a balanced net ionic equation?

• Identify spectator ions

• Balance the molecular equation

• Determine the solubility of products

• Write the states of substances

Which of the following is a strong acid?

• Strontium hydroxide

• Sulfuric acid

• Water

• Strontium sulfate

What is the state of strontium sulfate in the reaction?

• Liquid

• Solid

• Gas

• Aqueous

What charge does the sulfate ion carry?

• 1+

• 2-

• 2+

• 1-

What is the charge of the strontium ion?

• 1+

• 2+

• 1-

• 2-

Which ion is not split in the net ionic equation?

• Hydrogen ion

• Sulfate ion

• Strontium sulfate

• Hydroxide ion

What is the role of spectator ions in a net ionic equation?

• They are removed as they do not change

• They are the main reactants

• They are included in the final equation

• They form the precipitate

What ensures the net ionic equation is balanced?

• Presence of spectator ions

• Unequal number of atoms on both sides

• Equal number of atoms on both sides

• Different charges on both sides

What is the final product in the net ionic equation?

• Hydrogen ion

• Strontium ion

• Water

• Strontium sulfate

What is the state of water in the net ionic equation?

• Aqueous

• Solid

• Liquid

• Gas