Net Ionic Equations and Solubility Concepts

Net Ionic Equations and Solubility Concepts

Assessment

Interactive Video

Chemistry

10th - 11th Grade

Hard

Created by

Sophia Harris

FREE Resource

This video tutorial guides viewers through balancing the net ionic equation for the reaction between iron(III) hydroxide and sulfuric acid. It begins with balancing the molecular equation, determining the states of substances, and using solubility rules. The tutorial then explains how to split strong electrolytes into ions to form the complete ionic equation. It identifies spectator ions to derive the net ionic equation, ensuring charge and mass balance. The video concludes with a review of the balanced net ionic equation, emphasizing the importance of recognizing insoluble compounds.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in balancing the molecular equation for iron(III) hydroxide and sulfuric acid?

Balance the hydrogen atoms.

Balance the sulfate ions.

Balance the oxygen atoms.

Balance the iron atoms.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is iron(III) hydroxide considered insoluble?

It reacts with water.

It forms a precipitate.

It dissolves completely.

It is a strong acid.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the state of sulfuric acid in the reaction?

Solid

Gas

Liquid

Aqueous

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you determine if a substance is slightly soluble?

By heating it.

By measuring its pH.

By checking a solubility chart.

By observing its color.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of splitting strong electrolytes into ions?

To balance the equation.

To change the reaction temperature.

To increase the reaction rate.

To form the complete ionic equation.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which ions are not split in the complete ionic equation?

Strong acids

Weak bases

Insoluble solids

Spectator ions

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why are there no spectator ions in this reaction?

The ions are all insoluble.

The ions are all soluble.

All ions are involved in the reaction.

The reaction is not balanced.

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