Net Ionic Equations and Reactions

This video tutorial guides viewers through writing a balanced net ionic equation for the reaction between aluminum and copper(II) nitrate. It begins with balancing the molecular equation, assigning states to each substance, and then splitting strong electrolytes into ions to form the complete ionic equation. Spectator ions are eliminated to derive the net ionic equation, ensuring conservation of mass and charge. The tutorial emphasizes understanding the process of balancing equations and the role of different ions in the reaction.

What is the first step in writing a net ionic equation?

• Determine the states of substances

• Balance the molecular equation

• Split strong electrolytes into ions

• Identify spectator ions

What is the state of aluminum in the reaction?

• Gas

• Aqueous

• Solid

• Liquid

Which type of reaction occurs between aluminum and copper II nitrate?

• Decomposition

• Single displacement

• Synthesis

• Double displacement

What charge does the nitrate ion carry?

• 2+

• 1+

• 2-

• 1-

How many nitrate ions are present in the reactants of the complete ionic equation?

• Three

• Four

• Five

• Six

What is the purpose of removing spectator ions?

• To determine the states of substances

• To balance the equation

• To simplify the equation

• To identify the reaction type

Which ions are removed as spectator ions in this reaction?

• Hydrogen ions

• Nitrate ions

• Aluminum ions

• Copper ions

What is conserved in the net ionic equation?

• Only mass

• Both mass and charge

• Only charge

• Neither mass nor charge

How many aluminum atoms are present on each side of the net ionic equation?

• One

• Two

• Four

• Three

What is the final charge on the product side of the net ionic equation?

• 12+

• 6+

• 9+

• 3+