Atoms in Nickel Phosphate Compounds

The video tutorial explains how to determine the number of atoms in the compound Ni3(PO4)2, known as nickel(II) phosphate. It begins by identifying the elements present: nickel, phosphorus, and oxygen. The tutorial then calculates the number of each type of atom in the compound, considering subscripts and parentheses. It concludes with a method to find the number of phosphorus atoms in one mole of Ni3(PO4)2 using Avogadro's number. The video is presented by Dr. B, who provides a clear and concise explanation of the process.

What is the chemical formula for nickel(II) phosphate?

• Ni3(PO3)2

• Ni(PO4)2

• Ni2(PO4)3

• Ni3(PO4)2

How many nickel atoms are present in Ni3(PO4)2?

• 1

• 2

• 3

• 4

What is the total number of oxygen atoms in Ni3(PO4)2?

• 4

• 10

• 6

• 8

How many total atoms are there in one formula unit of Ni3(PO4)2?

• 13

• 11

• 10

• 12

Which element in Ni3(PO4)2 has the highest number of atoms?

• Oxygen

• Phosphorus

• Hydrogen

• Nickel

If you have one mole of Ni3(PO4)2, how many phosphorus atoms would you have?

• 2 times Avogadro's number

• 4 times Avogadro's number

• 3 times Avogadro's number

• 5 times Avogadro's number

What is the role of Avogadro's number in calculating the number of atoms in a mole?

• It is used to find the mass of a mole.

• It is used to calculate the density of a mole.

• It is used to convert moles to atoms.

• It is used to find the volume of a mole.