Chemical Composition and Atomic Structure

Chemical Composition and Atomic Structure

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Liam Anderson

FREE Resource

The video tutorial explains how to determine the number of atoms in calcium hydroxide (Ca(OH)2). It begins by identifying the types of atoms present: calcium, oxygen, and hydrogen. The tutorial then details how to count these atoms, considering the chemical formula and subscripts. It further explains how to calculate the number of oxygen atoms in one mole of calcium hydroxide using Avogadro's number. The video concludes with a summary of the findings.

Read more

7 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the types of atoms present in calcium hydroxide?

Calcium, Nitrogen, Hydrogen

Calcium, Oxygen, Hydrogen

Calcium, Oxygen, Helium

Carbon, Oxygen, Hydrogen

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does it mean when there is no subscript after an element in a chemical formula?

The element is present in two units

The element is present in one unit

The element is not present

The element is present in three units

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many oxygen atoms are there in one molecule of Ca(OH)2?

Two

Four

One

Three

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many hydrogen atoms are present in one molecule of calcium hydroxide?

Four

Three

Two

One

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the total number of atoms in a single molecule of Ca(OH)2?

Six

Three

Four

Five

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you calculate the number of oxygen atoms in one mole of Ca(OH)2?

Add Avogadro's number to the number of oxygen atoms

Divide the number of oxygen atoms by Avogadro's number

Subtract Avogadro's number from the number of oxygen atoms

Multiply the number of oxygen atoms by Avogadro's number

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is Avogadro's number approximately?

6.02 x 10^24

6.02 x 10^23

6.02 x 10^25

6.02 x 10^22