Net Ionic Equations and Spectator Ions

Net Ionic Equations and Spectator Ions

Assessment

Interactive Video

Chemistry

10th - 12th Grade

Hard

Created by

Lucas Foster

FREE Resource

This video tutorial explains how to balance net ionic equations, specifically for the reaction between copper(II) hydroxide and hydrochloric acid. It covers writing the balanced molecular equation, determining the states of compounds using a solubility table, and splitting strong electrolytes into ions to form the complete ionic equation. The tutorial concludes with identifying and removing spectator ions to derive the net ionic equation.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in balancing a net ionic equation?

Write the complete ionic equation

Write the balanced molecular equation

Identify spectator ions

Determine the states of compounds

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it important to check the solubility of hydroxides?

They are always soluble

They are always gases

They are often insoluble, especially with transition metals

They never dissociate into ions

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the 's' state symbol indicate for a compound?

The compound is insoluble

The compound is a gas

The compound is soluble

The compound is aqueous

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is a strong electrolyte?

Copper(II) hydroxide

Hydrochloric acid

Water

Copper(II) oxide

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What charge does a chlorine ion typically have?

Positive

Negative

Variable

Neutral

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of splitting compounds into ions?

To balance the equation

To identify the molecular equation

To form the complete ionic equation

To determine the solubility

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are spectator ions?

Ions that form a precipitate

Ions that are gases

Ions that change state during the reaction

Ions that do not participate in the reaction

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