Net Ionic Equations and Solubility

The video tutorial explains how to write a net ionic equation for the reaction between copper(II) chloride and potassium phosphate. It begins with balancing the molecular equation, determining the solubility of reactants and products, and identifying the charges of ions. The tutorial then demonstrates how to write the complete ionic equation, identify spectator ions, and derive the net ionic equation. Key concepts include solubility rules, ion charges, and the distinction between complete and net ionic equations.

What is the first step in writing a net ionic equation for a reaction?

• Determine the solubility of compounds

• Assign charges to ions

• Balance the molecular equation

• Identify spectator ions

Which of the following compounds is insoluble in water?

• Potassium chloride

• Copper(II) phosphate

• Potassium phosphate

• Copper(II) chloride

What is the state of copper(II) chloride in the reaction?

• Liquid

• Aqueous

• Solid

• Gas

What is the charge of the phosphate ion?

• 4-

• 2-

• 1-

• 3-

How many chloride ions are present in the complete ionic equation for the reaction?

• 8

• 6

• 2

• 4

What do we call ions that appear on both sides of the complete ionic equation?

• Net ions

• Spectator ions

• Soluble ions

• Precipitate ions

Which ions are removed to derive the net ionic equation?

• All ions

• Only cations

• Spectator ions

• Only anions

What is the net ionic equation primarily used to show?

• Only the soluble compounds

• The ions that do not change

• Only the precipitate formation

• All reactants and products

Why don't we split solids in the net ionic equation?

• They do not dissolve in water

• They are gases

• They are not reactive

• They are spectator ions

What happens to the precipitate in a chemical reaction?

• It evaporates

• It remains in solution

• It dissolves in water

• It falls to the bottom