Ionic Compounds and Reactions

The video tutorial explains how to write a net ionic equation for the reaction between silver nitrate (AgNO3) and sodium chloride (NaCl). It begins by balancing the molecular equation, then assigns states to each compound, identifying which are aqueous and which are solid. The tutorial proceeds to split the soluble compounds into their respective ions, highlighting the charges of each ion. Spectator ions, which appear on both sides of the equation, are identified and removed. Finally, the net ionic equation is presented, showing only the ions that participate in the reaction.

What is the first step in writing a net ionic equation?

• Assign charges to ions

• Balance the molecular equation

• Write the net ionic equation

• Identify spectator ions

Which of the following compounds is not soluble in water?

• AgNO3

• NaCl

• AgCl

• NaNO3

What does the state 'aq' indicate about a compound?

• It is a gas

• It is soluble in water

• It is a solid

• It is insoluble in water

What charge does the nitrate ion (NO3) carry?

• 1-

• 2+

• 1+

• 2-

Which group on the periodic table does sodium (Na) belong to?

• Group 18

• Group 17

• Group 2

• Group 1

What is the charge of a silver ion (Ag)?

• 1+

• 2+

• 2-

• 1-

Which of the following is a spectator ion in the reaction?

• Ag+

• AgCl

• Cl-

• Na+

What happens to spectator ions in a net ionic equation?

• They change their charge

• They are removed from the equation

• They are included in the equation

• They form a precipitate

What is the final net ionic equation for the reaction between AgNO3 and NaCl?

• Ag+ + NO3- → AgNO3

• AgNO3 + NaCl → AgCl + NaNO3

• Na+ + NO3- → NaNO3

• Ag+ + Cl- → AgCl

Who is the presenter of the video tutorial?

• Dr. D

• Dr. C

• Dr. B

• Dr. A