Balancing Chemical Equations and Decomposition

The video tutorial explains the decomposition of iron(II) sulfate into iron(III) oxide, sulfur dioxide, and sulfur trioxide. It guides viewers through the process of balancing the chemical equation by counting the atoms on each side and adjusting coefficients to ensure both sides are equal. The tutorial concludes with the balanced equation and a brief sign-off from Dr. B.

What are the products formed when iron(II) sulfate decomposes?

• FeO, SO2, and SO3

• Fe2O3, SO3, and O2

• Fe2O3, SO2, and SO3

• FeO, SO3, and O2

What is the first step in balancing a chemical equation?

• Remove extra compounds

• Add coefficients randomly

• Count the atoms of each element on both sides

• Change the chemical formulas

How many sulfur atoms are present on the product side before balancing?

• One

• Two

• Four

• Three

What is the coefficient placed in front of FeSO4 to balance the equation?

• 1

• 2

• 3

• 4

After balancing, how many oxygen atoms are there on each side of the equation?

• Four

• Ten

• Six

• Eight

What is the final balanced equation for the decomposition of FeSO4?

• 2FeSO4 → Fe2O3 + 2SO2 + SO3

• FeSO4 → Fe2O3 + SO2 + SO3

• 2FeSO4 → Fe2O3 + SO2 + SO3

• 2FeSO4 → Fe2O3 + SO2 + 2SO3