Balancing Chemical Equations Practice

Balancing Chemical Equations Practice

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Emma Peterson

FREE Resource

The video tutorial explains how to balance a chemical equation involving sodium and sodium hydroxide. It begins by counting the atoms on each side of the equation and identifies the need to balance hydrogen atoms first. The instructor then adjusts coefficients to balance the oxygen and sodium atoms, ensuring the equation is balanced. The tutorial concludes with a review of the balanced equation, emphasizing the importance of balancing all elements involved.

Read more

9 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial number of sodium atoms on the reactant side before balancing?

One

Two

Four

Three

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many hydrogen atoms are present on the product side before balancing?

Three

Four

One

Two

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What coefficient is placed in front of sodium hydroxide to balance the hydrogen atoms?

4

3

2

1

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After balancing hydrogen, how many oxygen atoms are there on the reactant side?

Four

One

Two

Three

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the total number of sodium atoms on the reactant side after updating the sodium count?

Two

Three

Five

Four

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What coefficient is placed in front of Na2O to balance the oxygen atoms?

3

2

1

4

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many sodium atoms are there on the product side after balancing?

Two

Three

Four

Five

8.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final coefficient placed in front of sodium on the reactant side to balance the equation?

1

2

3

4

9.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the balanced chemical equation for the reaction between sodium and sodium hydroxide?

4Na + 2NaOH → 2Na2O + H2

2Na + 2NaOH → Na2O + H2

2Na + 2NaOH → 2Na2O + H2

Na + NaOH → Na2O + H2