Lead(IV) Fluoride and Ionic Compounds

The video tutorial explains how to write the chemical formula for lead(IV) fluoride. It begins by identifying lead and fluorine on the periodic table, noting that lead is a transition metal with a charge of 4+ and fluorine has a charge of 1-. The tutorial then describes the formation of ionic compounds and the importance of balancing charges to achieve a neutral compound. The crisscross method is introduced to determine the correct subscripts for the formula PbF4. Finally, the video verifies the formula by ensuring the charges balance to zero, confirming the correct formula for lead(IV) fluoride.

Which element is represented by the symbol 'Pb' on the periodic table?

• Platinum

• Lead

• Phosphorus

• Palladium

What type of compound is formed when a metal and a non-metal combine?

• Covalent

• Molecular

• Ionic

• Metallic

What is the ionic charge of lead in lead(IV) fluoride?

• 2+

• 3+

• 4+

• 1+

What is the charge of fluorine when it forms an ion?

• 0

• 3-

• 2-

• 1-

What method is used to balance the charges in the formula for lead(IV) fluoride?

• Substitution method

• Addition method

• Cross-multiplication

• Crisscross method

In the crisscross method, what happens to the charges of the ions?

• They are ignored

• They are swapped as subscripts

• They are subtracted

• They are added together

How many fluorine atoms are needed to balance the charge of one lead atom in lead(IV) fluoride?

• 4

• 3

• 2

• 1

What is the net charge of the compound lead(IV) fluoride?

• 4+

• 4-

• 0

• 1-

What is the correct chemical formula for lead(IV) fluoride?

• PbF3

• Pb2F4

• PbF4

• PbF2