Ionic Reactions and Equations

This video tutorial explains how to write and balance a molecular equation for the reaction between barium chloride and aluminum sulfate. It covers the steps to assign states to compounds, split them into ions, and write both the complete and net ionic equations. The tutorial also highlights the importance of balancing coefficients and identifying spectator ions.

What are the coefficients for the balanced molecular equation of barium chloride and aluminum sulfate?

• 3, 1, 3, 2

• 2, 3, 1, 3

• 1, 2, 3, 3

• 3, 2, 1, 3

Which compound in the reaction forms a solid precipitate?

• Aluminum sulfate

• Barium chloride

• Barium sulfate

• Aluminum chloride

What is the charge of the barium ion in the reaction?

• 0

• 3+

• 2+

• 1+

Which ion has a charge of 1- in the reaction?

• Aluminum

• Sulfate

• Chlorine

• Barium

What is the charge of the aluminum ion in the reaction?

• 1+

• 2+

• 3+

• 4+

How many chloride ions are present in the complete ionic equation?

• 4

• 3

• 6

• 5

What is the total number of sulfate ions in the complete ionic equation?

• 1

• 2

• 3

• 4

Which ions are considered spectator ions in this reaction?

• Chloride and aluminum

• Barium and sulfate

• Barium and aluminum

• Sulfate and chloride

What is the net ionic equation primarily composed of?

• Spectator ions

• Reactants only

• Products only

• Reactants and products minus spectator ions

Which of the following is not a step in writing a net ionic equation?

• Balancing the molecular equation

• Identifying spectator ions

• Writing the complete ionic equation

• Adding more reactants