Lewis Structure of SeF2

Lewis Structure of SeF2

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Aiden Montgomery

FREE Resource

The video tutorial explains how to write the Lewis structure for selenium difluoride (SeF2). It begins by counting the valence electrons of selenium and fluorine, totaling 20. Selenium is placed in the center with fluorine atoms on either side. Electrons are distributed to form bonds and complete the octet for each atom. The process uses all 20 valence electrons, resulting in a complete Lewis structure for SeF2.

Read more

6 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many valence electrons does selenium contribute in the Lewis structure of SeF2?

4

6

7

8

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the total number of valence electrons used in the Lewis structure of SeF2?

16

18

20

22

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which atom is placed at the center of the SeF2 Lewis structure?

Hydrogen

Oxygen

Selenium

Fluorine

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many pairs of electrons are placed between selenium and each fluorine atom to form bonds?

2

1

4

3

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many valence electrons are used to complete the octet for selenium in SeF2?

4

2

6

8

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final step in completing the Lewis structure for SeF2?

Removing extra electrons

Adding more fluorine atoms

Changing the central atom

Ensuring each atom has an octet