Oxidation States and SF6

The video tutorial explains how to determine the oxidation numbers for elements in sulfur hexafluoride (SF6). It begins by identifying the oxidation number of fluorine as -1 and then uses the neutrality of the compound to calculate sulfur's oxidation number as +6. The tutorial concludes with a recap of the process used to find these oxidation numbers.

What is the central element in SF6?

• Sulfur

• Nitrogen

• Oxygen

• Fluorine

How many fluorine atoms are present in SF6?

• Five

• Four

• Six

• Seven

What is the oxidation state of fluorine in SF6?

• -1

• +1

• 0

• +2

Why must the oxidation numbers in SF6 add up to zero?

• Because SF6 is an ionic compound

• Because SF6 is a neutral compound

• Because SF6 is a charged compound

• Because SF6 is a polar compound

What is the oxidation number of sulfur in SF6?

• -6

• +4

• 0

• +6

What principle is used to determine the oxidation number of sulfur in SF6?

• The sum of oxidation numbers in a neutral compound is zero

• The sum of oxidation numbers in an ionic compound is zero

• The sum of oxidation numbers in a polar compound is zero

• The sum of oxidation numbers in a charged compound is zero