Balancing Chemical Reactions and Equations

Balancing Chemical Reactions and Equations

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Amelia Wright

FREE Resource

The video tutorial explains how to balance a chemical equation involving lead metal and silver nitrate, resulting in lead(II) nitrate and silver metal. It is a single displacement reaction. The tutorial guides viewers through counting atoms, simplifying the process by treating the nitrate group as a single unit, and balancing the equation by adjusting coefficients. The video concludes with tips on handling polyatomic ions in equations.

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8 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What type of reaction is lead metal plus silver nitrate?

Synthesis reaction

Single displacement reaction

Double displacement reaction

Decomposition reaction

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of the nitrate group in the equation?

It is a monatomic ion

It is a polyatomic ion

It is a catalyst

It is a reactant

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many nitrate groups are present on the product side before balancing?

Three

Two

Four

One

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What coefficient is placed in front of AgNO3 to balance the nitrates?

3

2

4

1

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many silver atoms are on the reactant side after balancing?

Two

Three

One

Four

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final coefficient in front of Ag to balance the equation?

1

2

3

4

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it easier to count polyatomic ions as single units?

It reduces the number of calculations

It simplifies the balancing process

It increases the reaction rate

It changes the reaction type

8.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the balanced equation for the reaction between lead metal and silver nitrate?

Pb + 2AgNO3 → Pb(NO3)2 + 2Ag

Pb + AgNO3 → Pb(NO3)2 + Ag

2Pb + AgNO3 → Pb(NO3)2 + 2Ag

Pb + AgNO3 → Pb(NO3)2 + 2Ag