Balancing Chemical Equations

The video tutorial demonstrates how to balance the chemical equation C12H22O11 yielding C plus H2O. It begins by counting the atoms on both sides of the equation, identifying 12 carbons, 22 hydrogens, and 11 oxygens on the reactant side, and 1 carbon, 2 hydrogens, and 1 oxygen on the product side. The tutorial then balances the hydrogens by placing a coefficient of 11 in front of H2O, which also updates the oxygen count. Finally, it balances the carbons by adding a coefficient of 12 in front of carbon, resulting in a balanced equation.

What is the initial count of carbon atoms on the reactant side of the equation?

• 1

• 22

• 12

• 11

How many hydrogen atoms are present on the reactant side before balancing?

• 11

• 2

• 12

• 22

What coefficient is added in front of water to balance the hydrogen atoms?

• 22

• 12

• 2

• 11

After balancing hydrogen, how many oxygen atoms are there on the product side?

• 22

• 11

• 12

• 1

What coefficient is used to balance the carbon atoms in the equation?

• 1

• 11

• 22

• 12

What is the final balanced equation for C12H22O11 yielding C plus H2O?

• C12H22O11 -> 12C + H2O

• C12H22O11 -> C + H2O

• C12H22O11 -> C + 11H2O

• C12H22O11 -> 12C + 11H2O