Balancing Chemical Equations

The video tutorial explains how to balance a combustion reaction involving C3H4 and O2, resulting in CO2 and H2O. It begins by counting the atoms on both sides of the equation, then proceeds to balance the carbon, hydrogen, and oxygen atoms step by step. The tutorial concludes with the final balanced equation, ensuring that the number of atoms for each element is equal on both sides.

What are the initial counts of carbon, hydrogen, and oxygen atoms on the reactant side of the equation?

• 3 carbons, 2 hydrogens, 4 oxygens

• 1 carbon, 2 hydrogens, 3 oxygens

• 2 carbons, 4 hydrogens, 3 oxygens

• 3 carbons, 4 hydrogens, 2 oxygens

How many carbon atoms are present on the product side before balancing?

• Three

• One

• Two

• Four

What coefficient is placed in front of CO2 to balance the carbon atoms?

• 1

• 3

• 4

• 2

After balancing carbon, how many total oxygen atoms are on the product side?

• 6

• 5

• 8

• 7

What coefficient is used in front of H2O to balance the hydrogen atoms?

• 1

• 2

• 3

• 4

How many hydrogen atoms are there on the product side after balancing?

• Two

• Four

• Eight

• Six

What is the final coefficient placed in front of O2 to balance the equation?

• 2

• 3

• 5

• 4

What is the balanced chemical equation for the combustion of C3H4?

• C3H4 + 4O2 → 2CO2 + 3H2O

• C3H4 + 5O2 → 3CO2 + 4H2O

• C3H4 + 3O2 → 3CO2 + 2H2O

• C3H4 + 4O2 → 3CO2 + 2H2O