Balancing Chemical Equations

The video tutorial demonstrates how to balance a chemical equation involving beryllium and oxygen gas to form beryllium oxide. It begins by counting the atoms on each side of the equation and then adjusts the coefficients to balance the oxygen atoms first, followed by the beryllium atoms. The process is explained step-by-step, ensuring that the number of atoms for each element is equal on both sides of the equation. The tutorial concludes with a summary of the balanced equation.

What is the initial number of oxygen atoms on the reactant side of the equation?

• Four

• One

• Two

• Three

What is the initial number of beryllium atoms on the product side of the equation?

• One

• Two

• Four

• Three

What change is made to balance the oxygen atoms in the equation?

• Add a coefficient of 3 in front of BeO

• Add a coefficient of 2 in front of O2

• Add a coefficient of 2 in front of BeO

• Add a coefficient of 3 in front of O2

After balancing the oxygen atoms, how many oxygen atoms are there on each side of the equation?

• Three

• One

• Two

• Four

What coefficient is added in front of beryllium to balance the equation?

• One

• Two

• Four

• Three

What is the final balanced chemical equation?

• Be + 2O2 → BeO2

• 2Be + 2O2 → 2BeO2

• 2Be + O2 → 2BeO

• Be + O2 → BeO