Balancing Chemical Equations and Ions

Balancing Chemical Equations and Ions

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Emma Peterson

FREE Resource

The video tutorial explains how to balance a chemical equation involving potassium hydroxide and copper(II) sulfate. It begins by counting the atoms on both the reactant and product sides, treating certain groups like hydroxide and sulfate as single units to simplify the process. The tutorial then demonstrates how to balance the equation by adjusting coefficients, ensuring the number of each type of atom is equal on both sides. The balanced equation is presented as KOH + CuSO4 yields Cu(OH)2 + K2SO4. The tutorial concludes by emphasizing the efficiency of this method over counting individual atoms.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial chemical equation that needs to be balanced?

NaCl + AgNO3 → NaNO3 + AgCl

H2 + O2 → H2O

KOH + CuSO4 → Cu(OH)2 + K2SO4

C + O2 → CO2

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many potassium atoms are present on the reactant side initially?

Four

One

Two

Three

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

On the product side, how many hydroxide ions are initially present?

One

Two

Three

Four

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What imbalance is identified between potassium and hydroxide ions on the product side?

Twice as many hydroxides as potassiums

Equal number of hydroxides and potassiums

Twice as many potassiums as hydroxides

More sulfates than hydroxides

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What coefficient is added in front of KOH to balance the equation?

4

3

2

1

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After balancing, how many potassium atoms are on each side of the equation?

Three

One

Two

Four

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final balanced chemical equation?

KOH + CuSO4 → 2Cu(OH)2 + K2SO4

2KOH + CuSO4 → Cu(OH)2 + 2K2SO4

2KOH + CuSO4 → Cu(OH)2 + K2SO4

KOH + CuSO4 → Cu(OH)2 + K2SO4

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