Balancing Chemical Equations Practice

The video tutorial explains how to balance a chemical equation involving strontium and water, resulting in strontium hydroxide and hydrogen gas. It begins by counting the atoms on each side of the equation, highlighting common mistakes, and then demonstrates how to balance hydrogen and oxygen atoms by adjusting coefficients. The tutorial concludes with the balanced equation and a brief summary.

What are the initial counts of strontium, hydrogen, and oxygen atoms on the reactant side of the equation?

• 1 strontium, 2 hydrogens, 1 oxygen

• 2 strontiums, 1 hydrogen, 2 oxygens

• 1 strontium, 1 hydrogen, 2 oxygens

• 2 strontiums, 2 hydrogens, 1 oxygen

On the product side, how many hydrogen atoms are there before balancing?

• 4

• 3

• 5

• 2

What is a common mistake when counting hydrogen atoms in this equation?

• Forgetting to double the hydrogen atoms in the hydroxide

• Adding extra hydrogen atoms

• Counting the oxygen atoms twice

• Ignoring the strontium atoms

What coefficient is used to balance the water molecules in the equation?

• 2

• 3

• 4

• 1

After balancing, how many oxygen atoms are present on each side of the equation?

• 1

• 4

• 3

• 2

What is the final balanced chemical equation for the reaction between strontium and water?

• Sr + H2O → Sr(OH)2 + H2

• 2Sr + 2H2O → 2Sr(OH)2 + H2

• Sr + 2H2O → Sr(OH)2 + 2H2

• 2Sr + H2O → Sr(OH)2 + 2H2