Balancing Chemical Equations Practice

Balancing Chemical Equations Practice

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Aiden Montgomery

FREE Resource

The video tutorial explains how to balance a chemical equation involving strontium and water, resulting in strontium hydroxide and hydrogen gas. It begins by counting the atoms on each side of the equation, highlighting common mistakes, and then demonstrates how to balance hydrogen and oxygen atoms by adjusting coefficients. The tutorial concludes with the balanced equation and a brief summary.

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6 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the initial counts of strontium, hydrogen, and oxygen atoms on the reactant side of the equation?

1 strontium, 2 hydrogens, 1 oxygen

2 strontiums, 1 hydrogen, 2 oxygens

1 strontium, 1 hydrogen, 2 oxygens

2 strontiums, 2 hydrogens, 1 oxygen

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

On the product side, how many hydrogen atoms are there before balancing?

4

3

5

2

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is a common mistake when counting hydrogen atoms in this equation?

Forgetting to double the hydrogen atoms in the hydroxide

Adding extra hydrogen atoms

Counting the oxygen atoms twice

Ignoring the strontium atoms

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What coefficient is used to balance the water molecules in the equation?

2

3

4

1

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After balancing, how many oxygen atoms are present on each side of the equation?

1

4

3

2

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final balanced chemical equation for the reaction between strontium and water?

Sr + H2O → Sr(OH)2 + H2

2Sr + 2H2O → 2Sr(OH)2 + H2

Sr + 2H2O → Sr(OH)2 + 2H2

2Sr + H2O → Sr(OH)2 + 2H2