Balancing Chemical Equations

The video tutorial explains how to balance a chemical equation involving ammonia and fluorine gas, resulting in hydrofluoric acid and nitrogen trifluoride. It begins by counting the atoms on each side of the equation, then adjusts coefficients to balance hydrogen and fluorine atoms. The tutorial concludes with the final balanced equation and a brief summary.

What are the initial counts of nitrogen, hydrogen, and fluorine atoms on the reactant side of the equation?

• 3 nitrogens, 1 hydrogen, 2 fluorines

• 1 nitrogen, 2 hydrogens, 3 fluorines

• 2 nitrogens, 3 hydrogens, 1 fluorine

• 1 nitrogen, 3 hydrogens, 2 fluorines

How many hydrogen atoms are present on the product side before balancing?

• 1 hydrogen

• 2 hydrogens

• 3 hydrogens

• 4 hydrogens

What coefficient is placed in front of HF to balance the hydrogen atoms?

• 3

• 5

• 2

• 4

After adjusting the coefficient for HF, how many fluorine atoms are on the product side?

• 7 fluorines

• 5 fluorines

• 4 fluorines

• 6 fluorines

What coefficient is used in front of F2 to balance the fluorine atoms?

• 2

• 3

• 5

• 4

What is the final balanced equation for the reaction?

• NH3 + 2F2 → 2HF + NF3

• 2NH3 + 3F2 → 6HF + 2NF3

• NH3 + F2 → HF + NF3

• NH3 + 3F2 → 3HF + NF3

What is the total number of fluorine atoms on each side of the balanced equation?

• 4 fluorines

• 5 fluorines

• 7 fluorines

• 6 fluorines