Balancing Chemical Equations Concepts

Balancing Chemical Equations Concepts

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Sophia Harris

FREE Resource

The video tutorial explains how to balance a chemical equation involving ammonia and sulfuric acid to yield ammonium sulfate. It begins by counting the atoms on both sides of the equation, identifying imbalances, and then adjusting coefficients to achieve balance. The process involves balancing nitrogen and hydrogen atoms first, which resolves the equation. The tutorial concludes with a summary of the balanced equation.

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9 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial number of hydrogen atoms on the reactant side before balancing?

3

5

6

8

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many nitrogen atoms are present on the product side before any adjustments?

1

2

3

4

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first element adjusted to help balance the equation?

Hydrogen

Sulfur

Nitrogen

Oxygen

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After balancing nitrogen, how many hydrogen atoms are there on the reactant side?

8

7

6

5

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which element's count remains unchanged throughout the balancing process?

Sulfur

Hydrogen

Oxygen

Nitrogen

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final balanced chemical equation?

NH3 + H2SO4 → NH4HSO4

2NH3 + H2SO4 → (NH4)2SO4

NH3 + 2H2SO4 → NH4HSO4

2NH3 + 2H2SO4 → 2(NH4)2SO4

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of balancing nitrogen first in this equation?

It reduces the number of steps.

It helps in balancing hydrogen.

It automatically balances sulfur.

It simplifies the oxygen count.

8.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the total number of oxygen atoms on the product side after balancing?

2

8

4

6

9.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it important to balance chemical equations?

To ensure the reaction is fast.

To conserve mass and atoms.

To increase the yield.

To reduce energy consumption.