Valence Electrons in N2O4 Structure

Valence Electrons in N2O4 Structure

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Jackson Turner

FREE Resource

The video tutorial explains the process of drawing the Lewis structure for N2O4. It begins by identifying the total number of valence electrons and placing nitrogen atoms in the center with oxygen atoms surrounding them. The tutorial demonstrates how to distribute electrons to form chemical bonds and complete the octets for oxygen atoms. It then addresses the incomplete octets for nitrogen atoms and shows how to form double bonds to satisfy the octet rule for all atoms. The final structure uses all 34 valence electrons, ensuring each atom has a complete octet.

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6 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the total number of valence electrons in the N2O4 molecule?

32

34

38

36

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which element is placed at the center of the N2O4 Lewis structure?

Carbon

Hydrogen

Oxygen

Nitrogen

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many oxygen atoms are present in the N2O4 molecule?

4

3

2

5

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of placing valence electrons between atoms in the N2O4 structure?

To decrease the atomic number

To change the element

To form chemical bonds

To increase the atomic mass

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why are double bonds formed between nitrogen and oxygen in the N2O4 structure?

To increase the number of oxygen atoms

To complete the octets for nitrogen

To change the molecular shape

To reduce the number of electrons

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After forming double bonds, how many valence electrons does each nitrogen atom have in the N2O4 structure?

9

7

8

6