C2 2- Lewis Structure Concepts

C2 2- Lewis Structure Concepts

Assessment

Interactive Video

Chemistry

10th - 12th Grade

Hard

Created by

Jackson Turner

FREE Resource

The video tutorial explains the process of drawing the Lewis structure for the C2 2- ion, also known as the dicarbide ion. It begins by calculating the total number of valence electrons and placing them between two carbon atoms to form bonds. The tutorial demonstrates how to achieve an octet for each carbon atom by forming double and triple bonds. Finally, it discusses the importance of symmetry and the use of brackets to indicate the ion's charge.

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7 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many total valence electrons are used in the C2 2- Lewis structure?

8

10

14

12

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What group on the periodic table does carbon belong to?

Group 4 or 14

Group 2

Group 8

Group 6

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial step in forming the C2 2- Lewis structure?

Placing two electrons between the carbon atoms

Forming a triple bond immediately

Adding extra electrons to one carbon

Creating a double bond first

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it necessary to form a triple bond in the C2 2- Lewis structure?

To make the structure more complex

To increase the number of valence electrons

To achieve an octet for both carbon atoms

To reduce the number of valence electrons

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many bonds are formed between the carbon atoms in the final C2 2- Lewis structure?

Two double bonds

No bonds

One triple bond

One single bond

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of placing brackets around the C2 2- Lewis structure?

To make it look symmetrical

To highlight the central bond

To indicate it is a molecule

To show it is an ion

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of moving electron pairs to the ends of the structure?

To make the structure more compact

To reduce the number of valence electrons

To achieve a symmetrical appearance

To increase the number of bonds