BrF3 Lewis Structure and Valence Electrons

BrF3 Lewis Structure and Valence Electrons

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Liam Anderson

FREE Resource

The video explains the process of drawing the Lewis structure for BrF3. It starts by identifying the total number of valence electrons and placing Bromine at the center due to its lower electronegativity. Fluorine atoms are placed around Bromine, and single bonds are formed. The remaining valence electrons are distributed, with Bromine accommodating more than eight electrons due to its position in period 4. The video concludes by confirming that all formal charges are zero, indicating a stable structure.

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5 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many total valence electrons are present in the BrF3 molecule?

32

30

28

26

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which atom is placed at the center of the BrF3 Lewis structure?

Bromine

Iodine

Chlorine

Fluorine

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why can Bromine have more than 8 valence electrons in BrF3?

It is in period 3 of the periodic table.

It is in period 4 of the periodic table.

It is a noble gas.

It is highly electronegative.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many pairs of valence electrons are left after placing single bonds between Bromine and Fluorine?

Four pairs

Three pairs

One pair

Two pairs

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formal charge on each atom in the BrF3 Lewis structure?

+2

0

-1

+1