Valence Electrons and Lewis Structures

Valence Electrons and Lewis Structures

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Liam Anderson

FREE Resource

The video tutorial explains how to draw the Lewis structure for NOBr. It begins by identifying the valence electrons for nitrogen, oxygen, and bromine, totaling 18. Nitrogen, being the least electronegative, is placed in the center with oxygen and bromine on either side. Initial bonds are formed using valence electrons, and adjustments are made to ensure each atom achieves an octet. A double bond is formed between nitrogen and oxygen to resolve the octet issue. The final structure is verified by checking that the formal charges on each atom are zero, confirming it as the best structure.

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6 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many valence electrons does Nitrogen have in the NOBr molecule?

3

5

7

8

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which atom is placed at the center of the NOBr Lewis structure?

Hydrogen

Nitrogen

Bromine

Oxygen

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many valence electrons are initially used to form chemical bonds in NOBr?

6

4

8

2

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of forming a double bond in the NOBr structure?

To satisfy the octet rule for Bromine

To decrease the number of valence electrons

To satisfy the octet rule for Nitrogen

To increase the number of valence electrons

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After forming the double bond, how many valence electrons does Nitrogen have?

8

9

7

6

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formal charge on each atom in the finalized NOBr structure?

+1

0

+2

-1