Cross-Multiplying and Chemical Reactions

Cross-Multiplying and Chemical Reactions

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Amelia Wright

FREE Resource

The video tutorial explains how to calculate the number of moles of a substance produced using a balanced chemical equation. It involves setting up a ratio based on the given moles of carbon and solving for the unknown moles of carbon monoxide. The process includes cross-multiplying and verifying the solution to ensure it makes logical sense.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main goal of the problem discussed in the video?

To calculate the volume of carbon dioxide produced

To find the mass of carbon monoxide produced

To identify the limiting reactant in the reaction

To determine the number of moles of carbon monoxide produced

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial amount of carbon given in the problem?

3.00 moles

5.42 moles

2.71 moles

1.81 moles

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which equation is used to set up the ratio for solving the problem?

x/2 = 3/2.71

2/3 = x/2.71

2.71/3 = x/2

3/2.71 = 2/x

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of the balanced equation in solving the problem?

It provides the exact mass of reactants needed

It helps in setting up the correct ratio for calculation

It determines the temperature at which the reaction occurs

It identifies the products formed in the reaction

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of cross-multiplying the equation 3/2.71 = 2/x?

3x = 5.42

2x = 5.42

3x = 2.71

2x = 2.71

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final calculated value of x, representing the moles of carbon monoxide?

5.42 moles

3.00 moles

1.81 moles

2.71 moles

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What mathematical operation is used to isolate x in the equation 3x = 5.42?

Division

Addition

Subtraction

Multiplication

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