Understanding Averages and Fractions

Understanding Averages and Fractions

Assessment

Interactive Video

Mathematics

6th - 7th Grade

Hard

Created by

Aiden Montgomery

FREE Resource

The video tutorial explains how to calculate averages, focusing on the challenges of adding fractions with different denominators. It discusses converting fractions to a common denominator and performing calculations. The tutorial also reviews final answers and explores percentage calculations, emphasizing the importance of understanding recurring and terminating decimals.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in calculating an average?

Subtract the smallest number from the largest

Divide all numbers by the total count

Add all the numbers together

Multiply all numbers

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why might converting fractions to decimals be problematic?

Decimals are always larger than fractions

Decimals can be recurring and difficult to work with

Decimals require a calculator

Decimals are harder to add than fractions

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the advantage of keeping numbers in 'fraction land'?

Fractions are easier to divide

Fractions avoid recurring decimals

Fractions are more accurate than decimals

Fractions are easier to multiply

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the term for a decimal that stops?

Repeating

Recurring

Infinite

Terminating

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is a common multiple of 4, 3, and 7?

21

42

56

84

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you convert a fraction to have a common denominator?

Divide the numerator by the denominator

Multiply the numerator and denominator by the same number

Subtract the denominators

Add the numerators together

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After finding a common denominator and adding fractions, what is the next step to find the average?

Multiply the sum by the number of terms

Divide the sum by the number of terms

Subtract the smallest fraction

Add the number of terms to the sum

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