Simple Harmonic Motion and Spring Systems

Simple Harmonic Motion and Spring Systems

Assessment

Interactive Video

Physics

9th - 10th Grade

Hard

Created by

Aiden Montgomery

FREE Resource

The video tutorial explores the dynamics of a spring and weight system, focusing on simple harmonic motion. It begins with a conceptual introduction, followed by modeling the motion without considering air resistance. The tutorial defines a coordinate system and explains the concept of simple harmonic motion. It then demonstrates how to integrate to find velocity as a function of displacement and applies initial conditions to solve for constants. The tutorial aims to help students understand the principles of motion and calculus in a practical context.

Read more

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial setup of the experiment involving the spring and weight?

A weight is placed on a spring and compressed.

A weight is attached to a spring and suspended from a ceiling.

A weight is attached to a spring and submerged in water.

A weight is attached to a spring and placed on a table.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to the spring and weight system when the weight is lifted and released?

The weight remains stationary.

The weight moves in a circular path.

The weight falls and stays at the lowest point.

The weight oscillates up and down.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What type of motion is exhibited by the spring and weight system?

Circular motion

Linear motion

Simple harmonic motion

Random motion

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it convenient to set the resting point of the object as x equals zero?

It makes the system more complex.

It changes the nature of the motion.

It has no effect on the calculations.

It simplifies calculations by eliminating constants.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the mathematical expression used to model the system's motion?

v = 2x

a = 4x

v^2 = -4x

x = 2v

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial condition used to solve for the constant in the velocity equation?

The weight is at rest at its highest point.

The weight is moving at a constant speed.

The weight is at rest at its lowest point.

The weight is moving at maximum speed.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the constant in the velocity equation determined?

By using the initial condition where the weight is at rest.

By measuring the time taken for one oscillation.

By calculating the maximum speed of the weight.

By observing the weight's behavior over time.

Create a free account and access millions of resources

Create resources
Host any resource
Get auto-graded reports
or continue with
Microsoft
Apple
Others
By signing up, you agree to our Terms of Service & Privacy Policy
Already have an account?