Parametric and Quadratic Concepts

Parametric and Quadratic Concepts

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Practice Problem

Hard

Created by

Aiden Montgomery

FREE Resource

The video tutorial explains the difference between Cartesian and parametric approaches to solving problems involving parabolas. It demonstrates how to derive the parametric equation of a parabola and find the equation of a tangent using this method. The tutorial further explores how to identify specific tangents that pass through a given point and solve the resulting quadratic equation. The focus is on using parameters to simplify the process and achieve the desired results efficiently.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main difference between the Cartesian and parametric approaches?

Cartesian uses parameters, parametric does not.

Parametric uses parameters, Cartesian does not.

Neither uses parameters.

Both use parameters.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the focal length when x squared equals 12y?

2

3

4

5

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the parametric form, what is the gradient at point P?

2P

3P

4P

P

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the coordinate form for every point on the parabola when a is 3?

5P, 2P squared

6P, 3P squared

7P, 3P squared

4P, 2P squared

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of the parameter in the parametric form?

It is irrelevant.

It is used to find the vertex.

It defines the gradient.

It determines the focal length.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which point do the two specific tangents pass through?

(1, -1)

(2, -2)

(3, -1)

(2, -1)

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What equation form is used to find every tangent on the parabola?

y = mx + c

ax^2 + bx + c = 0

mx + b

x^2 = 4ay

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