The video tutorial explains how to solve a problem related to the enthalpy of combustion of glucose. It begins by introducing the problem and the necessary standard enthalpies of formation. The instructor then writes and balances the combustion reaction for glucose. Following this, a thermochemical analysis is performed to calculate the enthalpy change using the standard enthalpies of formation of the products and reactants. Finally, the enthalpy of combustion is converted from per mole to per gram of glucose, providing the final answer.

What are the standard enthalpies of formation for carbon dioxide, liquid water, and solid glucose at 25 degrees Celsius?

• Negative 500, negative 200, and negative 1,200 kJ/mol

• Negative 600, negative 100, and negative 1,000 kJ/mol

• Negative 300, negative 400, and negative 1,400 kJ/mol

• Negative 400, negative 300, and negative 1,300 kJ/mol

What is the chemical formula for glucose used in the combustion reaction?

• C5H10O5

• C5H12O6

• C6H10O5

• C6H12O6

In a combustion reaction, what are the typical products formed?

• Carbon monoxide and hydrogen

• Carbon dioxide and water

• Oxygen and hydrogen

• Methane and water

How is the standard enthalpy change for a reaction calculated?

• Sum of enthalpies of formation of products minus sum of enthalpies of formation of reactants

• Difference between enthalpies of formation of reactants and products

• Sum of enthalpies of formation of reactants minus sum of enthalpies of formation of products

• Product of enthalpies of formation of reactants and products

What is the coefficient of carbon dioxide in the balanced combustion equation for glucose?

• 6

• 8

• 4

• 2

What is the enthalpy of combustion for glucose per mole?

• Negative 3000 kJ/mol

• Negative 2700 kJ/mol

• Negative 2900 kJ/mol

• Negative 2800 kJ/mol

What is the molar mass of glucose used in the conversion calculation?

• 200 grams per mole

• 160 grams per mole

• 150 grams per mole

• 180 grams per mole

How do you convert the enthalpy of combustion from per mole to per gram?

• Subtract the molar mass of glucose

• Divide by the molar mass of glucose

• Multiply by the molar mass of glucose

• Add the molar mass of glucose

What is the final enthalpy of combustion per gram of glucose?

• Negative 17.11 kJ/g

• Negative 15.11 kJ/g

• Negative 16.11 kJ/g

• Negative 18.11 kJ/g

Why is the enthalpy of formation for oxygen considered zero?

• Because it is a liquid

• Because it is an element in its standard state

• Because it is a gas

• Because it is a compound