Limits and Trigonometric Functions

Limits and Trigonometric Functions

Assessment

Interactive Video

Mathematics

11th - 12th Grade

Hard

Created by

Aiden Montgomery

FREE Resource

The video tutorial explores trigonometric relationships, focusing on the identities involving sine and cosine. It discusses the impact of dividing by sine on inequalities and introduces the concept of limits, particularly for small values of x. The Squeeze Theorem is explained in detail, demonstrating how it applies to trigonometric functions. The tutorial concludes with examples of applying limits to different trigonometric expressions, emphasizing the importance of understanding these concepts in calculus.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the basic relationship between sine and cosine in trigonometry?

Sine and cosine are equal

Sine divided by cosine equals tangent

Sine is the reciprocal of cosine

Sine is the tangent of cosine

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When dividing through by sine x, why does the direction of the inequality remain unchanged?

Because sine x is a constant

Because sine x is always negative

Because sine x is zero

Because sine x is positive for small x

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What mathematical concept is used to describe values approaching zero?

Derivatives

Integrals

Limits

Functions

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to the value of 1 as x approaches zero?

It becomes negative

It becomes infinite

It remains unchanged

It becomes zero

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the Squeeze Theorem used to demonstrate in this context?

That x over sine x approaches one

That x over sine x approaches infinity

That x over sine x approaches negative one

That x over sine x approaches zero

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How does the Squeeze Theorem apply to the limit of x over tan x?

It shows that the limit is negative one

It shows that the limit is infinite

It shows that the limit is one

It shows that the limit is zero

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What can be done to simplify the limit of 2x over sine x?

Multiply by sine x

Add 2 to the expression

Subtract 2 from the expression

Factor out the 2

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