Electronegativity and Ionic Compounds

Electronegativity and Ionic Compounds

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Liam Anderson

FREE Resource

The video explores whether cesium fluoride (CsF) is ionic or covalent. By examining the periodic table, cesium is identified as a metal and fluorine as a non-metal, suggesting an ionic bond. The electronegativity difference between cesium (0.79) and fluorine (3.98) is calculated to be 3.19, which is well above the threshold for ionic bonds. Therefore, CsF is confirmed to be an ionic compound.

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6 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What type of elements are involved in forming cesium fluoride?

Two non-metals

A metalloid and a non-metal

A metal and a non-metal

Two metals

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the electronegativity value of cesium?

3.98

0.79

2.0

1.7

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you calculate the difference in electronegativity between two elements?

Multiply their electronegativity values

Subtract the smaller value from the larger one

Divide the larger value by the smaller one

Add their electronegativity values

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the electronegativity difference between cesium and fluorine?

1.7

2.0

3.19

0.79

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

According to the scale used, what electronegativity difference indicates an ionic bond?

Above 2.0

Below 1.7

Exactly 1.7

Above 1.7

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What type of compound is cesium fluoride?

Polar covalent

Ionic

Covalent

Metallic