Oxidation States of Lead and Sulfur

The video tutorial explains how to find the oxidation number for lead in PbS2, a neutral compound. It discusses the rules for determining oxidation numbers, especially for transition metals like lead, which can have various oxidation states. The tutorial highlights the importance of electronegativity in binary compounds and uses sulfur's ionic charge to deduce the oxidation state of lead. The calculation shows that lead in PbS2 has an oxidation number of +4. The video concludes with a thank you from Dr. B.

What is the overall charge of the compound PbS2?

• Positive

• Variable

• Negative

• Neutral

Why is lead not listed with a fixed oxidation state?

• It is a non-metal.

• It is a transition metal with variable oxidation states.

• It always has a fixed oxidation state.

• It is not found in the periodic table.

How do we determine the oxidation state of sulfur in PbS2?

• By assuming it is always -1.

• By assuming it is always +2.

• By using the charge of sulfur as an ion.

• By looking at the color of the compound.

What is the ionic charge of sulfur used in the calculation?

• -2

• -1

• +1

• +2

What must be the oxidation number of lead in PbS2 to balance the charges?

• 0

• -2

• +4

• +2

What is the final oxidation number of lead in PbS2?

• +4

• +5

• +3

• +2