Net Ionic Equations and Charge Balance

Net Ionic Equations and Charge Balance

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Lucas Foster

FREE Resource

This video tutorial explains how to write a balanced net ionic equation for the reaction between potassium iodide (KI) and copper(II) sulfate (CuSO4). It covers balancing the molecular equation, determining the states of substances, and splitting strong electrolytes into ions to form the complete ionic equation. The tutorial concludes with deriving the net ionic equation by removing spectator ions, ensuring charge and mass conservation.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of writing a net ionic equation?

To highlight the formation of precipitates

To balance the charges in a reaction

To show all compounds involved in a reaction

To simplify the reaction by removing spectator ions

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it necessary to balance the molecular equation first?

To identify the limiting reactant

To ensure the reaction occurs

To determine the reaction rate

To conserve mass and charge

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following compounds is insoluble in water?

Copper(II) sulfate (CuSO4)

Copper(II) iodide (CuI2)

Potassium iodide (KI)

Sodium chloride (NaCl)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the charge on the sulfate ion (SO4) in the complete ionic equation?

2+

2-

1-

1+

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which ions are considered spectator ions in this reaction?

Potassium ions (K+)

Iodide ions (I-)

Copper ions (Cu2+)

Sulfate ions (SO4 2-)

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the net ionic equation for the reaction between KI and CuSO4?

2I- + Cu2+ → CuI2

Cu2+ + 2I- → CuI2

K+ + SO4 2- → K2SO4

2KI + CuSO4 → CuI2 + K2SO4

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why do we not split solids in net ionic equations?

They do not dissociate in water

They are not involved in the reaction

They are already balanced

They are spectator ions

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