Net Ionic Equations and Spectator Ions

The video tutorial explains how to write a balanced net ionic equation for the reaction between lead(II) nitrate and sodium bromide. It begins with balancing the molecular equation, then discusses the solubility of the substances involved to determine their states. The tutorial proceeds to form the complete ionic equation by splitting strong electrolytes into ions. Spectator ions are identified and removed to derive the net ionic equation. The video concludes by ensuring the conservation of charge and mass in the final equation.

What is the first step in writing a balanced net ionic equation?

• Determine the solubility of compounds

• Identify spectator ions

• Balance the molecular equation

• Write the complete ionic equation

Why is it important to know the solubility of compounds in a reaction?

• To identify the precipitate formed

• To decide the temperature of the reaction

• To calculate the reaction rate

• To determine the color of the solution

Which of the following is considered a strong electrolyte?

• Sodium nitrate

• Sodium bromide

• Lead(II) bromide

• Lead(II) nitrate

How do you determine the charge of a transition metal in a compound?

• By its position in the periodic table

• By the charge of the ions it is bonded to

• By its atomic number

• By its color in solution

What is the charge of the nitrate ion?

• 1+

• 2+

• 2-

• 1-

What are spectator ions?

• Ions that change color

• Ions that do not change during the reaction

• Ions that participate in the reaction

• Ions that form a precipitate

Which ions are removed to form the net ionic equation?

• All ions

• Only the ions that form a solid

• Spectator ions

• Ions with a positive charge

What must be conserved in a balanced net ionic equation?

• Only mass

• Only charge

• Both mass and charge

• Neither mass nor charge

What is the net ionic equation for the reaction between lead(II) nitrate and sodium bromide?

• Pb^2+ + 2Br^- → PbBr2

• Pb^2+ + 2NO3^- → Pb(NO3)2

• 2Na^+ + 2Br^- → 2NaBr

• Na^+ + Br^- → NaBr

Why is it important to ensure charge conservation in a net ionic equation?

• To balance the equation

• To maintain electrical neutrality

• To predict the products

• To ensure the reaction occurs