Net Ionic Equations and Reactions

Net Ionic Equations and Reactions

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Jackson Turner

FREE Resource

The video tutorial explains how to write the net ionic equation for the reaction between sodium bicarbonate (NaHCO3) and hydrochloric acid (HCl). It begins with balancing the molecular equation, followed by assigning states to each substance. The tutorial then demonstrates how to split strong electrolytes into ions and write the complete ionic equation. Spectator ions are identified and crossed out to derive the net ionic equation. The final net ionic equation is presented, showing the reaction between bicarbonate and hydrogen ions to form carbon dioxide and water.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in writing a net ionic equation?

Split strong electrolytes into ions

Write the states of substances

Identify spectator ions

Balance the molecular equation

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is true about sodium compounds in water?

They are insoluble

They remain as molecules

They form a precipitate

They are soluble and split into ions

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the state of carbon dioxide in the reaction?

Gas

Aqueous

Liquid

Solid

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you determine the charge of the bicarbonate ion?

By checking its solubility

By assuming it is neutral

By using a table of common polyatomic ions

By looking at the periodic table

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the charge of sodium in the reaction?

0

1-

2+

1+

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of writing a complete ionic equation?

To balance the molecular equation

To identify the states of substances

To determine the solubility of compounds

To identify and remove spectator ions

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which ions are considered spectator ions in this reaction?

H+ and CO2

Na+ and H+

Na+ and Cl-

HCO3- and H2O

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