Net Ionic Equations and Spectator Ions

This video tutorial explains how to write the net ionic equation for the reaction between copper(II) oxide and hydrochloric acid. It begins with balancing the molecular equation, assigning states to each substance, and writing the complete ionic equation. The tutorial then covers determining ion charges and identifying spectator ions, leading to the final net ionic equation. The video concludes with a clean presentation of the net ionic equation.

What is the first step in writing the net ionic equation for a reaction?

• Balance the molecular equation

• Split strong electrolytes into ions

• Identify spectator ions

• Determine the states of substances

What is the state of copper(II) oxide in the reaction?

• Aqueous

• Gas

• Liquid

• Solid

Which of the following substances will dissociate completely in water?

• Water

• All of the above

• Hydrochloric acid

• Copper(II) oxide

What is the charge of the hydrogen ion in hydrochloric acid?

• 2+

• 1+

• 2-

• 1-

In the complete ionic equation, which ions are not split apart?

• None of the above

• All ions

• Solid, gas, and liquid substances

• Aqueous ions

What is the charge of the copper ion in the complete ionic equation?

• 1+

• 2-

• 2+

• 1-

What are spectator ions?

• Ions that are present on both sides of the equation but do not participate

• Ions that are only in the reactants

• Ions that are only in the products

• Ions that participate in the reaction

Which ions are crossed out to derive the net ionic equation?

• All ions

• Only the reactant ions

• Spectator ions

• Product ions

What is the final step in writing the net ionic equation?

• Balancing the molecular equation

• Splitting strong electrolytes into ions

• Identifying spectator ions

• Cleaning up and adding states

What is the purpose of writing a net ionic equation?

• To balance the molecular equation

• To show all ions present in the reaction

• To highlight the substances that do not change

• To focus on the ions that participate in the reaction