Oxidation Numbers and Ionic Compounds

Oxidation Numbers and Ionic Compounds

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Olivia Brooks

FREE Resource

The video tutorial explains how to determine the oxidation numbers for each element in sodium bromide (NaBr). It begins by noting that NaBr is a neutral compound, meaning the oxidation numbers must sum to zero. Sodium, being in group 1, has an oxidation number of +1, while bromine, in group 17, has an oxidation number of -1. The video concludes by confirming that these oxidation numbers add up to zero, consistent with NaBr being a neutral compound.

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5 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the overall charge of the compound NaBr?

Neutral

Variable

Negative

Positive

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the oxidation number of sodium in NaBr?

+1

-1

0

+2

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which group does bromine belong to, and what is its oxidation number in NaBr?

Group 2, +2

Group 1, +1

Group 16, -2

Group 17, -1

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why do the oxidation numbers in NaBr add up to zero?

Because NaBr is a charged compound

Because NaBr is a neutral compound

Because NaBr is an ionic compound

Because NaBr is a covalent compound

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of the oxidation numbers adding up to zero in NaBr?

It indicates a charged compound

It confirms the compound is neutral

It shows the compound is unstable

It suggests the compound is reactive