Balancing Decomposition Reactions

The video tutorial explains how to balance a decomposition reaction involving iron(III) hydroxide breaking down into iron(III) oxide and water. It begins by counting the atoms on each side of the equation, focusing on iron, oxygen, and hydrogen. The tutorial then demonstrates how to balance the equation by adjusting coefficients, ensuring that the number of each type of atom is equal on both sides. The process involves balancing iron first, followed by oxygen and hydrogen, resulting in a balanced chemical equation.

What is the initial decomposition reaction being balanced in the video?

• Fe(OH)3 -> Fe2O3 + H2O

• Fe(OH)3 + H2O -> Fe2O3

• Fe2O3 -> Fe(OH)3 + H2O

• H2O -> Fe(OH)3 + Fe2O3

How many iron atoms are present on the product side initially?

• Four

• Three

• Two

• One

What is the first step taken to balance the equation?

• Balancing the oxygen atoms

• Adjusting the coefficient of H2O

• Balancing the iron atoms

• Balancing the hydrogen atoms

After balancing the iron atoms, how many oxygen atoms are there on the reactant side?

• Four

• Three

• Five

• Six

What coefficient is used to balance the hydrogen atoms?

• 2

• 4

• 3

• 1

How many hydrogen atoms are there on each side after balancing?

• Eight

• Four

• Six

• Two

What is the final count of oxygen atoms on the product side?

• Six

• Five

• Four

• Seven

What is the final balanced equation for the decomposition of Fe(OH)3?

• 2Fe(OH)3 -> Fe2O3 + 3H2O

• Fe(OH)3 -> 2Fe2O3 + 3H2O

• Fe(OH)3 -> Fe2O3 + H2O

• 2Fe(OH)3 -> 2Fe2O3 + 3H2O