Valence Electrons in BH2- Structure

Valence Electrons in BH2- Structure

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Mia Campbell

FREE Resource

The video tutorial explains how to write the Lewis structure for BH2-. It begins by counting the valence electrons: boron has three, each hydrogen has one, and the negative charge adds an extra electron, totaling six. Boron is placed in the center with hydrogens on either side. Two electrons form bonds between boron and each hydrogen, and the remaining two electrons are placed on boron. The video highlights that boron and hydrogen are exceptions to the octet rule, requiring only six and two electrons, respectively, to be stable.

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7 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many valence electrons does boron contribute in the BH2- ion?

3

4

1

2

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the total number of valence electrons in BH2-?

4

6

5

7

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Where is boron placed in the BH2- Lewis structure?

On the left

On the right

Above hydrogen

In the center

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many valence electrons are used to form bonds between boron and hydrogen in BH2-?

6

4

2

8

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the exception to the octet rule for boron in BH2-?

It needs 4 electrons

It needs 8 electrons

It needs 6 electrons

It needs 2 electrons

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many valence electrons does hydrogen need to be stable in BH2-?

1

2

3

4

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final electron configuration for hydrogen in the BH2- structure?

3 electrons

2 electrons

1 electron

4 electrons