
Balancing Chemical Equations

Interactive Video
•
Chemistry
•
9th - 10th Grade
•
Hard

Mia Campbell
FREE Resource
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8 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the initial number of oxygen atoms on the reactant side in the decomposition of potassium chlorate?
Three
Two
Four
One
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why is it beneficial to convert an odd number of oxygen atoms to an even number when balancing equations?
It makes the equation more complex.
It simplifies the balancing process.
It increases the number of steps required.
It is not beneficial.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What coefficient is placed in front of KClO3 to start balancing the equation?
Two
One
Four
Three
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
After applying the coefficient to KClO3, how many oxygen atoms are there on the reactant side?
Four
Six
Seven
Five
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What coefficient is used in front of O2 to balance the oxygen atoms?
Two
Four
Three
One
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How many potassium atoms are present on the product side after balancing?
One
Two
Three
Four
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the final coefficient placed in front of KCl to balance the equation?
Two
One
Three
Four
8.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the key trick mentioned for making the balancing of equations easier?
Using odd numbers for oxygen atoms.
Using even numbers for oxygen atoms.
Ignoring oxygen atoms.
Balancing only potassium atoms.
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