Oxidation Numbers in Na2CrO4

The video tutorial explains how to determine the oxidation numbers for sodium chromate (Na2CrO4). It begins by introducing the concept of oxidation numbers and the general rules used to determine them. The tutorial highlights that sodium, being in group one, has an oxidation number of +1, while oxygen typically has an oxidation number of -2. Using these rules, the video demonstrates how to calculate the oxidation number of chromium in the compound by ensuring the sum of all oxidation numbers in the neutral compound equals zero. The tutorial concludes with a recap of the steps taken to find the oxidation number of chromium.

What is the oxidation number of sodium in Na2CrO4?

• +1

• +2

• -1

• 0

Which element in Na2CrO4 typically has an oxidation number of -2?

• Hydrogen

• Chromium

• Sodium

• Oxygen

What is the total oxidation number for the four oxygen atoms in Na2CrO4?

• -4

• -6

• -8

• -2

How do the oxidation numbers in a neutral compound like Na2CrO4 add up?

• They add up to +2

• They add up to +1

• They add up to zero

• They add up to -1

What is the oxidation number of chromium in Na2CrO4?

• +4

• +2

• +3

• +6

Which rule helps determine the oxidation number of chromium in Na2CrO4?

• The rule that the sum of oxidation numbers in a neutral compound is zero

• The rule that oxygen is always -2

• The rule that sodium is always +1

• The rule that chromium is always +3

What is the main purpose of the video tutorial?

• To determine the oxidation numbers in Na2CrO4

• To teach chemical bonding

• To explain the properties of sodium

• To discuss the uses of chromate compounds