AlBr3 Structure and Valence Electrons

The video tutorial explains how to write the Lewis structure for aluminum bromide (AlBr3). It begins by counting the valence electrons: aluminum has 3 and each bromine has 7, totaling 24 valence electrons. The least electronegative element, aluminum, is placed in the center with three bromine atoms around it. Two electrons are placed between each atom to form chemical bonds, and the remaining electrons complete the octets for bromine. Aluminum is an exception to the octet rule, having only six valence electrons. The tutorial concludes with a reminder of this exception.

How many valence electrons does aluminum contribute in AlBr3?

• 3

• 5

• 1

• 7

What is the total number of valence electrons in AlBr3?

• 18

• 21

• 27

• 24

Which element is placed at the center of the AlBr3 structure?

• Bromine

• Fluorine

• Aluminum

• Chlorine

How many bromine atoms are arranged around the central aluminum atom in AlBr3?

• 3

• 2

• 1

• 4

How many valence electrons are left after forming bonds in AlBr3?

• 18

• 16

• 14

• 12

Why does aluminum not have a complete octet in AlBr3?

• It is an exception to the octet rule.

• It has too many electrons.

• It shares electrons with hydrogen.

• It forms a double bond with bromine.