Balancing Chemical Equations Practice

The video tutorial demonstrates how to balance the chemical equation H2 + S8 → H2S. It begins by counting the atoms on both sides of the equation, identifying the imbalance in sulfur atoms. The instructor explains how to adjust the coefficients to balance the sulfur atoms, resulting in 8 sulfurs on both sides. This adjustment also affects the hydrogen atoms, requiring further balancing. The instructor shows how to multiply the hydrogen coefficient to achieve balance, resulting in 16 hydrogens on both sides. The video concludes with a balanced equation and a brief summary.

What is the initial number of hydrogen atoms on the reactant side of the equation?

• 2

• 4

• 8

• 1

How many sulfur atoms are present on the reactant side before balancing?

• 8

• 1

• 2

• 4

What change is made to balance the sulfur atoms in the equation?

• Add a coefficient of 4 in front of H2S

• Add a coefficient of 8 in front of H2S

• Add a coefficient of 2 in front of H2S

• Add a coefficient of 6 in front of H2S

After balancing sulfur, how many hydrogen atoms are on the product side?

• 20

• 16

• 12

• 8

What coefficient is used in front of H2 to balance the hydrogen atoms?

• 10

• 8

• 6

• 4

What is the final balanced equation for H2 + S8 yields H2S?

• 2H2 + S8 → 2H2S

• 8H2 + S8 → 8H2S

• H2 + S8 → H2S

• 4H2 + S8 → 4H2S