8 сынып/12 сабақ/ Рационал-бөлшек теңдеулерді шешу

5 questions

Show all answers

1.

MULTIPLE SELECT QUESTION

1 min • 1 pt

Теңдеуді шешіңіз: $\frac{x+2}{x-3}-\frac{3}{x^2-3x}=\frac{x}{4}$

$x=6$

$x=-1$

$x=\frac{1}{2}$

$x=-2$

x = 2

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Мына теңдеудің шешімі қандай? $\frac{x+1}{2}=\frac{3}{2}$

$x=1$

$x=2$

$x=3$

$x=-4$

3.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

$\frac{x^2-4x}{x-1}=\frac{5}{x-1}$ теңдеуінің неше түбірі бар? ( $x\ne1$ )

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4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Қай теңдеудің шешімі x = 3?

$\frac{x}{3}=\frac{1}{3}$

$\frac{3}{x}=3$

$\frac{6}{x}=2$

$\frac{x}{2}=1$

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\frac{x+2}{x-3}=\frac{4}{x-3}$ осы теңдеудің неше түбірі бар?( $x\ne3$ )

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8 сынып/12 сабақ/ Рационал-бөлшек теңдеулерді шешу

5 questions

Теңдеуді шешіңіз: x+2x−3−3x2−3x=x4\frac{x+2}{x-3}-\frac{3}{x^2-3x}=\frac{x}{4}x−3x+2​−x2−3x3​=4x​

x = 2

Мына теңдеудің шешімі қандай? x+12=32\frac{x+1}{2}=\frac{3}{2}2x+1​=23​

x2−4xx−1=5x−1\frac{x^2-4x}{x-1}=\frac{5}{x-1}x−1x2−4x​=x−15​ теңдеуінің неше түбірі бар? ( x≠1x\ne1x=1 )

Қай теңдеудің шешімі x = 3?

x+2x−3=4x−3\frac{x+2}{x-3}=\frac{4}{x-3}x−3x+2​=x−34​ осы теңдеудің неше түбірі бар?( x≠3x\ne3x=3 )

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Discover more resources for Mathematics

Теңдеуді шешіңіз: $\frac{x+2}{x-3}-\frac{3}{x^2-3x}=\frac{x}{4}$

Мына теңдеудің шешімі қандай? $\frac{x+1}{2}=\frac{3}{2}$

$\frac{x^2-4x}{x-1}=\frac{5}{x-1}$ теңдеуінің неше түбірі бар? ( $x\ne1$ )

$\frac{x+2}{x-3}=\frac{4}{x-3}$ осы теңдеудің неше түбірі бар?( $x\ne3$ )