IIT/JEE Chemistry Practice #28: Gibbs Free Energy

The video tutorial explains how to solve a problem involving Gibbs free energy. It begins by introducing a chemical reaction at 300 Kelvin and provides the necessary data, including standard entropy change and Gibbs free energies of formation for CO2 and CO. The tutorial then demonstrates how to calculate the standard Gibbs free energy change using the products minus reactants method. Finally, it shows how to relate Gibbs free energy, enthalpy, and entropy to solve for the standard change in enthalpy, resulting in a value of -285.4 kJ/mol.

What new insight or understanding did you gain from this video?