Car Speed and Stopping Distance Analysis

Car Speed and Stopping Distance Analysis

Assessment

Interactive Video

Physics

9th - 10th Grade

Hard

Created by

Thomas White

FREE Resource

The video tutorial explains the relationship between a car's speed and its stopping distance, focusing on kinetic energy. It derives the formula for stopping distance and adjusts it for reaction time. The tutorial also covers how accident investigators use these formulas to determine a car's speed from skid marks. Finally, it demonstrates using a TI Nspire calculator to solve related problems.

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19 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to the stopping distance as the speed of a car increases?

It remains the same.

It increases.

It decreases.

It becomes zero.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary factor that causes a faster car to take longer to stop?

Engine power

Kinetic energy

Friction

Air resistance

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is kinetic energy mathematically expressed for a moving car?

KE = MV

KE = 1/2 MV^2

KE = MV^2

KE = M^2V

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the relationship between work done and kinetic energy in stopping a car?

Work done is less than kinetic energy.

Work done is equal to kinetic energy.

Work done is more than kinetic energy.

Work done is unrelated to kinetic energy.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the stopping distance formula D = V^2/2a represent?

The force required to stop a car.

The speed of a car when it stops.

The time it takes for a car to stop.

The distance a car travels before stopping.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is the stopping distance formula adjusted for real-world conditions?

To consider the car's weight.

To adjust for road conditions.

To account for air resistance.

To include the driver's reaction time.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the stopping distance formula modified to include reaction time?

D = V^2/2a + V^2

D = V^2/2a + 2/3 V

D = V^2/2a + 1/3 V

D = V^2/2a + V

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