Understanding Quadratic Word Problems

Understanding Quadratic Word Problems

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Practice Problem

Hard

Created by

Thomas White

FREE Resource

This video tutorial explores quadratic word problems involving area, focusing on solving for the dimensions of rectangles. It introduces the concept with a problem where the length is 8 inches more than the width, and the area is 48 square inches. The video demonstrates setting up the problem using variables, solving the quadratic equation using the box diamond method, and verifying the solution. A second problem is presented, where the length is one foot less than the width, and the area is 72 square feet. The video concludes with solving this problem using similar methods.

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9 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main focus of the video?

Exploring algebraic expressions

Learning about geometry

Understanding quadratic word problems involving area

Solving linear equations

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the first problem, how is the length of the rectangle related to its width?

The length is 8 inches more than the width

The length is twice the width

The length is 8 inches less than the width

The length is half the width

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What equation represents the area of the rectangle in the first problem?

w^2 - 8w = 0

w^2 + 8w = 0

w^2 + 8w = 48

w^2 - 8w = 48

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which method is used to solve the quadratic equation in the first problem?

Box-diamond method

Graphing

Substitution

Completing the square

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the valid width of the rectangle in the first problem?

16 inches

12 inches

8 inches

4 inches

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the second problem, how is the length of the rectangle related to its width?

The length is 1 foot more than the width

The length is equal to the width

The length is 1 foot less than the width

The length is twice the width

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What equation represents the area of the rectangle in the second problem?

w^2 - w = 72

w^2 + w = 0

w^2 + w = 72

w^2 - w = 0

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