Evaluating Inverse Functions and Trigonometry

Evaluating Inverse Functions and Trigonometry

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

Created by

Thomas White

FREE Resource

The video tutorial covers three essential tips for evaluating the composition of inverse functions. The first tip emphasizes understanding the restrictions on the domain of inverse trigonometric functions, using the unit circle for visualization. The second tip highlights the importance of recognizing when no solutions exist, particularly when dealing with values larger than one for sine and cosine. The third tip advises creating triangles to solve problems involving values not on the unit circle, utilizing the Pythagorean theorem to find missing sides.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first tip for evaluating the composition of inverse functions?

Memorize all trigonometric identities

Use a calculator for all calculations

Avoid using the unit circle

Know your restrictions

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it important to know the domain restrictions for inverse trigonometric functions?

To simplify calculations

To avoid using a calculator

To ensure correct angle evaluation

To memorize all angles

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the range of angles for the inverse sine function?

0 to 2π

-π/2 to π/2

0 to π

-π to π

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When evaluating the composition of inverse functions, what is the recommended approach?

Use a calculator

Work from the inside out

Guess the answer

Work from the outside in

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the example of sin(sin⁻¹(-1)), what is the result?

0

1

-1

π

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it important to know restrictions when graphing triangles?

To simplify calculations

To use more colors

To determine the correct orientation

To draw larger triangles

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens if the opposite side of a triangle is larger than the hypotenuse?

The hypotenuse is incorrect

The triangle is valid

The triangle is inverted

There is no solution

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